7=2x^+x

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Solution for 7=2x^+x equation: 



7=2x^+x

We move all terms to the left:

7-(2x^+x)=0

We get rid of parentheses

-2x^-x+7=0

We add all the numbers together, and all the variables

-3x+7=0

We move all terms containing x to the left, all other terms to the right

-3x=-7

x=-7/-3

x=2+1/3

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